3[b+1]=4b-1

Solution for 3[b+1]=4b-1 equation:

Simplifying
3[b + 1] = 4b + -1

Reorder the terms:
3[1 + b] = 4b + -1
[1 * 3 + b * 3] = 4b + -1
[3 + 3b] = 4b + -1

Reorder the terms:
3 + 3b = -1 + 4b

Solving
3 + 3b = -1 + 4b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-4b' to each side of the equation.
3 + 3b + -4b = -1 + 4b + -4b

Combine like terms: 3b + -4b = -1b
3 + -1b = -1 + 4b + -4b

Combine like terms: 4b + -4b = 0
3 + -1b = -1 + 0
3 + -1b = -1

Add '-3' to each side of the equation.
3 + -3 + -1b = -1 + -3

Combine like terms: 3 + -3 = 0
0 + -1b = -1 + -3
-1b = -1 + -3

Combine like terms: -1 + -3 = -4
-1b = -4

Divide each side by '-1'.
b = 4

Simplifying
b = 4